To compute the equivalent resistance for resistors in series, R_eq = R1 + R2 + R3. Compute R_eq for 2 Ω, 3 Ω, and 5 Ω.

To compute the equivalent resistance for resistors in series, R_eq = R1 + R2 + R3. Compute R_eq for 2 Ω, 3 Ω, and 5 Ω.

• A. 6 Ω
• B. 7 Ω
• C. 10 Ω
• D. 12 Ω

Answer: (C)

When resistors are in series, the same current flows through each one, so the total opposition to current is simply the sum of all the resistances. Add them all: 2 Ω + 3 Ω + 5 Ω = 10 Ω. That total, 10 ohms, is the equivalent resistance for the series arrangement. The numbers 6, 7, or 12 would only come from summing a different subset or from a different circuit arrangement (like parallel), which isn't the case here.

When resistors are in series, the same current flows through each one, so the total opposition to current is simply the sum of all the resistances. Add them all: 2 Ω + 3 Ω + 5 Ω = 10 Ω. That total, 10 ohms, is the equivalent resistance for the series arrangement. The numbers 6, 7, or 12 would only come from summing a different subset or from a different circuit arrangement (like parallel), which isn't the case here.